Question 6039 of 236 · California Water Treatment Operator Exam

A plant treats 2 MGD of water that has 0.1 mg/L natural fluoride and wants to reach 0.7 mg/L. How many pounds of fluoride ion must be added per day?

Exactly one answer is correct.

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Correct answer to question 6039

  • A: 10.0 lb/day

Explanation

The dose to add is 0.7 - 0.1 = 0.6 mg/L. lb/day = 2 x 0.6 x 8.34 = 10.0. Using 0.7 mg/L would give 11.7, and using 0.8 gives 13.3.

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