Question 6040 of 223 · California Water Treatment Operator Exam
Raw water turbidity is 12 NTU and the filtered water is 0.3 NTU. What is the percent removal?
Exactly one answer is correct.
You got of questions right. Here on the question pages nobody remembers which ones you got wrong. The trainer saves your progress and asks the mistakes again until they stick.
Or free: the 10 questions most people get wrong
Show solution
Correct answer to question 6040
- B: 97.5 percent
Explanation
Percent removal = (in - out) / in x 100 = (12 - 0.3) / 12 x 100 = 97.5. The 2.5 percent value is the percent remaining.
More questions: Treatment Exam Math
- 6041A reservoir covers 40 acres with an average depth of 12 ft. About how many million gallons does it hold? (1 acre-foot = 325,851 gal)
- 6042How much does 2,500 gallons of water weigh?
- 6043A hardness of 5 mg/L is equal to how many grains per gallon? (1 gpg = 17.1 mg/L)
- 6001A plant treats 2.5 MGD and the chlorine dose is 2.0 mg/L. How many pounds of chlorine are needed per day?
- 6002A well delivers 1.5 MGD and the desired chlorine dose is 3.5 mg/L. How many pounds of chlorine gas are needed per day?
- 6003A plant needs 20 lb/day of available chlorine and uses calcium hypochlorite that is 65 percent available chlorine. How many pounds of the hypochlorite are needed per day?