Question 6038 of 223 · California Water Treatment Operator Exam
How many pounds of chemical are in 3 MG of water dosed at 4 mg/L?
Exactly one answer is correct.
You got of questions right. Here on the question pages nobody remembers which ones you got wrong. The trainer saves your progress and asks the mistakes again until they stick.
Or free: the 10 questions most people get wrong
Show solution
Correct answer to question 6038
- D: 100 lb
Explanation
lb = 3 MG x 4 mg/L x 8.34 = 100.1 lb. Without the 8.34 factor the answer is 12.
More questions: Treatment Exam Math
- 6040Raw water turbidity is 12 NTU and the filtered water is 0.3 NTU. What is the percent removal?
- 6041A reservoir covers 40 acres with an average depth of 12 ft. About how many million gallons does it hold? (1 acre-foot = 325,851 gal)
- 6042How much does 2,500 gallons of water weigh?
- 6043A hardness of 5 mg/L is equal to how many grains per gallon? (1 gpg = 17.1 mg/L)
- 6001A plant treats 2.5 MGD and the chlorine dose is 2.0 mg/L. How many pounds of chlorine are needed per day?
- 6002A well delivers 1.5 MGD and the desired chlorine dose is 3.5 mg/L. How many pounds of chlorine gas are needed per day?