Question 9005 of 234 · California Wastewater Operator Exam
A circular clarifier has a diameter of 50 ft and receives 1.2 MGD. What is the surface overflow rate?
Exactly one answer is correct.
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Correct answer to question 9005
- C: 611 gpd/ft2
Explanation
Area = 0.785 x 50 x 50 = 1,963 ft2. Overflow rate = 1,200,000 gpd / 1,963 ft2 = 611 gpd/ft2. Using the radius in the 0.785 formula or the circumference instead of the area gives wrong results.
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