Question 9011 of 234 · California Wastewater Operator Exam
Sludge is 3.2 percent solids. What is the concentration in mg/L?
Exactly one answer is correct.
You got of questions right. Here on the question pages nobody remembers which ones you got wrong. The trainer saves your progress and asks the mistakes again until they stick.
Or free: the 10 questions most people get wrong
Show solution
Correct answer to question 9011
- A: 32,000 mg/L
Explanation
Percent solids x 10,000 = mg/L, so 3.2 x 10,000 = 32,000 mg/L.
More questions: Process Math and Unit Conversions
- 9012A flow of 2.4 MGD is equal to how many gallons per minute?
- 9013A flow of 900 gpm is equal to how many MGD?
- 9014Water flows in a channel 4 ft wide at a depth of 1.5 ft. The flow is 9 cfs. What is the velocity?
- 9015A cylindrical digester has a diameter of 40 ft and a sidewater depth of 25 ft. What is its volume in cubic feet?
- 9016A digester receives 2,200 lbs of volatile solids per day. Its volume is 15,000 ft3. What is the volatile solids loading rate?
- 9017A trickling filter receives 0.8 MGD with 150 mg/L BOD. Its media volume is 40,000 ft3. What is the organic loading in lbs BOD/day/1,000 ft3?