Question 6027 of 223 · California Water Treatment Operator Exam
A sedimentation basin with a surface area of 2,500 sq ft receives 1.0 MGD. What is the surface loading rate?
Exactly one answer is correct.
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Correct answer to question 6027
- A: 400 gpd/sq ft
Explanation
Surface loading rate = 1,000,000 gpd / 2,500 sq ft = 400 gpd/sq ft.
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