Question 7007 of 229 · California Water Distribution Operator Exam
How many pounds of chlorine gas are needed to dose 0.25 million gallons of water to 2.0 mg/L?
Exactly one answer is correct.
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Correct answer to question 7007
- C: 4.17 lb
Explanation
Pounds = MG x mg/L x 8.34 = 0.25 x 2.0 x 8.34 = 4.17 lb. Gas is 100 percent chlorine, so no purity correction applies.
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