Question 7006 of 229 · California Water Distribution Operator Exam
How many pounds of pure chlorine are needed to dose a 2,000-foot, 8-inch main to 25 mg/L?
Exactly one answer is correct.
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Correct answer to question 7006
- D: 1.09 lb
Explanation
Volume = 0.785 x 0.667^2 x 2,000 x 7.48 = 5,219 gallons = 0.00522 MG. Pounds = MG x mg/L x 8.34 = 0.00522 x 25 x 8.34 = 1.09 lb. Leaving out 8.34 is a common mistake.
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