Question 9022 of 234 · California Wastewater Operator Exam
An aeration tank holds 1.2 MG and the MLSS is 2,800 mg/L. How many pounds of MLSS are in the tank?
Exactly one answer is correct.
You got of questions right. Here on the question pages nobody remembers which ones you got wrong. The trainer saves your progress and asks the mistakes again until they stick.
Or free: the 10 questions most people get wrong
Show solution
Correct answer to question 9022
- A: 28,022 lbs
Explanation
Pounds = 8.34 x volume (MG) x concentration (mg/L) = 8.34 x 1.2 x 2,800 = 28,022 lbs.
More questions: Process Math and Unit Conversions
- 9023Flow is 2.0 MGD, primary effluent BOD is 200 mg/L, the aeration tank is 0.8 MG, and MLVSS is 2,100 mg/L. What is the F/M ratio?
- 9024The 30-minute settled volume is 280 mL/L and the MLSS is 2,800 mg/L. What is the sludge volume index?
- 9025A 1-liter sample of mixed liquor settles to 250 mL in 30 minutes. The MLSS is 2,000 mg/L. What is the sludge volume index (SVI)?
- 9026An activated sludge system has 37,530 lbs of solids in the aeration tank and 6,000 lbs in the clarifier. Solids leaving per day are 3,336 lbs in the waste sludge and 167 lbs in the effluent. What is the MCRT?
- 9027Waste activated sludge is pumped at 0.04 MGD with a concentration of 7,500 mg/L. How many pounds per day are wasted?
- 9028The return activated sludge flow is 1.2 MGD and the influent flow is 3.0 MGD. What is the return rate as a percent of influent flow?