Question 4024 of 223 · California Water Treatment Operator Exam
You need 500 mL of a 2 mg/L solution from a 100 mg/L stock. How many mL of stock are required?
Exactly one answer is correct.
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Correct answer to question 4024
- B: 10 mL
Explanation
C1V1 = C2V2 so V1 = (2 x 500) / 100 = 10 mL, diluted to 500 mL final. Using the ratio the wrong way gives 250.
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