Question 2011 of 223 · California Water Treatment Operator Exam
A sedimentation basin is 40 ft long, 20 ft wide and 12 ft deep and receives a flow of 0.5 MGD. What is its detention time?
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Correct answer to question 2011
- D: 3.4 hours
Explanation
Volume = 40 x 20 x 12 x 7.48 = 71,808 gal. Detention time = 71,808 gal / 500,000 gal/day = 0.1436 day, and 0.1436 x 24 = 3.4 hours. The unconverted 0.14 is in days.
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