Question 7026 of 229 · California Water Distribution Operator Exam
Water contains 0.5 mg/L of ammonia-nitrogen. How much chlorine is needed to reach a 4:1 chlorine to ammonia-nitrogen ratio?
Exactly one answer is correct.
You got of questions right. Here on the question pages nobody remembers which ones you got wrong. The trainer saves your progress and asks the mistakes again until they stick.
Or free: the 10 questions most people get wrong
Show solution
Correct answer to question 7026
- D: 2.0 mg/L
Explanation
Chlorine = ratio x ammonia-N = 4 x 0.5 = 2.0 mg/L. Dividing 0.5 by 4 gives 0.125, which inverts the ratio.
More questions: Distribution Math
- 7027A pressure gauge on a well discharge reads 18 psi at ground level, with the pump off and a closed valve. How many feet of water is above the gauge?
- 7028On a system map, 1 inch equals 400 feet. A main measures 3.5 inches on the map. What is the actual length?
- 7029A 120,000 gallon tank has 200 gpm flowing in and 700 gpm flowing out. How many hours until the full tank is empty?
- 7030A chemical feed pump delivers 120 mL per minute. How many gallons per day is this?
- 7031How many pounds of chlorine are needed to raise 2.4 MG of water by 1.5 mg/L?
- 7032How many mg/L are in a 0.5 percent chlorine solution?